9^x-2=(1/27)^x+4

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Solution for 9^x-2=(1/27)^x+4 equation: 



9^x-2=(1/27)^x+4

We move all terms to the left:

9^x-2-((1/27)^x+4)=0



Domain of the equation: 27)^x+4)!=0

x!=0/1

x!=0

x∈R



We add all the numbers together, and all the variables

9^x-((+1/27)^x+4)-2=0

We multiply all the terms by the denominator


9^x*27)^x+4)-((-2*27)^x+4)+1=0

We add all the numbers together, and all the variables

9^x*27)^x+4)-((-54)^x+4)+1=0

Wy multiply elements

243x^2-54)^x+4)+1=0

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